【Bonita BPM】如何取得Organization中的成員

tags: Bonita BPM

Common 基礎知識

1. Organization的架構：organization - groups - roles - users
2. 參考下圖，可以發現每個user都有自己的group和role
   
3. 可能會用到的import

import org.bonitasoft.engine.api.IdentityAPI
import org.bonitasoft.engine.identity.Group
import org.bonitasoft.engine.identity.Role
import org.bonitasoft.engine.identity.User
import org.bonitasoft.engine.identity.UserCriterion    

取得GroupName List

1. example code的Group為複數
2. 若只有1個Group可自行精簡code

def list = []
def groupPathList = ['/ServiceDepartment', '/SystemDepartment']
IdentityAPI identityAPI = apiAccessor.identityAPI
Group group = null

for(String groupPath : groupPathList) {
    group = identityAPI.getGroupByPath(groupPath)
    list.add('{"display":"' + group.getDisplayName() + '","id":' + group.getId() + '}')
}

return list

取得UserName List

1. 從 Group 取得 userList (example code為複數)

def list = []
def groupPathList = ['/ServiceDepartment', '/SystemDepartment']
IdentityAPI identityAPI = apiAccessor.identityAPI
List<User> userList = null
Group group = null

for(String groupPath : groupPathList) {
    group = identityAPI.getGroupByPath(groupPath)
    userList = identityAPI.getUsersInGroup(group.getId(), 0, Integer.MAX_VALUE, UserCriterion.USER_NAME_ASC)
    for(User user : userList) {		
        list.add('{"display":"' + user.getUserName() + '","department_id":' + group.getId() + '}')
    }
}

return list

2. 從 Role 取得 userList (example code為1個)
   同理，將group的部分改成role和role的method即可

def list = []
IdentityAPI identityAPI = apiAccessor.identityAPI
List<User> userList = null
Role role = null

role = identityAPI.getRoleByName('Director')
userList = identityAPI.getUsersInRole(role.getId(), 0, Integer.MAX_VALUE, UserCriterion.USER_NAME_ASC)
for(User user : userList) {	
    list.add('{"display":"' + user.getUserName() + '","department_id":' + role.getId() + '}')
}

return list

3. 補充：不取 UserName，改取 LastName + FirstName

StringBuilder userNameBuilder = new StringBuilder()
if(user.getLastName() != null) {
    userNameBuilder.append(user.getLastName())
}
if(user.getFirstName() != null) {
    userNameBuilder.append(user.getFirstName())
}
list.add('{"display":"' + userNameBuilder.toString() + '}')

取得SingleUser Id

1. 使用狀況：當Actors需要設定Actor filter為Single user

   

2. 我們可以稍微修改上面的code，來達到我們需求

3. 於for迴圈中，加入if判斷式去比對資料 userName

4. 承3，也可以用while寫寫看

5. 同理，也可以從role中篩選出Single user

long id

IdentityAPI identityAPI = apiAccessor.identityAPI
List<User> userList = null
Group group = null

group = identityAPI.getGroupByPath('/ServiceDepartment')
userList = identityAPI.getUsersInGroup(group.getId(), 0, Integer.MAX_VALUE, UserCriterion.USER_NAME_ASC)
for(User user : userList) {
    if(user.getUserName().equals("example")) {
        id = user.getId()
    }
}

return id

Related Links 補充

連結：【Bonita BPM】使用 identityAPI